Question

The sum of the digits of a 2- digit number is 8. If 18 is subtracted from this number, you get a number which is formed by interchanging the digits. Find the number.

Answer 1

Answer:

let the unit digit of the number be x

and tens digit be y

SO,

original number = 10y + x

and reversed number = 10x + y

ATQ,

x + y = 8 ........ i

and

10y + x - 18 = ( 10x + y)

=> 10 y + x - 10x - y = 18

=> 9y - 9x = 18

divide both by 9

then,

y - x = 2........ii

now,

add both the equation

we get,

2y = 10

=> y = 5

putting y = 5 in first equation

x + 5 = 8

=> x = 3

so, the original number is

10y + x

= 10× 5 + 3

= 53

soz the original number is 53 and reversed number is 35.

Answer 2

$\huge\underline\mathrm{SOLUTION:-}$

AnswEr:

• The original number = 53.

Given:

• The sum of the digits of a two-digit number is 8.
• If 18 is subtracted from the number, the digit of the number are interchanged.

Need To Find:

• The Number = ?

ExPlanation:

Let tens digit be x.

And the second be y.

➠ Number = 10x + y

According to the question:

x + y = 8 ..... (i)

10x + y - 18 = 10y + x

9x - 9y = 18

x - y = 2 .......(ii)

On Solving eq (i) and eq (ii), we get:

• x = 5 and y = 3

Number 10x + y = 10 × 5 + 3 = 53

• Hence, the original number is 53.

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