Math, asked by aadarsh528, 9 months ago

The sum of the digits of a 2-digit number is 8. The number obtained by
interchanging the digits exceeds the given number by 18. Find the given numbers.​

Answers

Answered by niva40
0

Answer:

10

Step-by-step explanation:

x+y=8

yx -x=18

following me

Answered by Anonymous
8

Step-by-step explanation:

Assume that the ten's digit number be x and one's digit number be y.

The sum of the digits of a two digit number is 8.

As per given condition,

→ x + y = 8

→ x = 8 - y ..............................(1)

The number obtained by interchanging the digits exceeds the given number by 18.

  • Original Number = 10x + y
  • Reversed Number = 10y + x

As per given condition,

→ 10y + x = 10x + y + 18

→ 10y + x - 10x - y = 18

→ 9y - 9x = 18

→ y - x = 18

Substitute value of x in above equation

→ y - 8 + y = 18

→ 2y = 10

→ y = 5

Substitute value of y in (1)

→ x = 8 - 5

→ x = 3

Hence, the original number is 35.

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