the sum of the digits of a 2-digit number is 8 . the number obtained by interchanging the digit exceeds the given number by 18 . find the given number
Answers
Answered by
1
Hey sup!
As per the question,
Such pairs whose sum is 8 are(0,8),(1,7),(2,6),(3,5), (4,4),(5,3),(6,2),(7,1),(8,0).
In such possible pairs only (3,5) fulfills our condition.
1)53-35=18.
So 35 is the number.
Hope it helps.
As per the question,
Such pairs whose sum is 8 are(0,8),(1,7),(2,6),(3,5), (4,4),(5,3),(6,2),(7,1),(8,0).
In such possible pairs only (3,5) fulfills our condition.
1)53-35=18.
So 35 is the number.
Hope it helps.
Answered by
0
➡HERE IS YOUR ANSWER⬇
Let us consider that the digits are x and y.
Then, the number is = (10x + y)
When, digits are interchanged, the number becomes (10y+x).
Given that :
x + y = 8 .....(i)
and
10y + x = (10x + y) + 18
=> 9y = 9x + 18
=> y = x + 2
Now, putting y = x + 2 in (i), we get :
x + x + 2 = 8
=> 2x = 6
=> x = 3
Hence, y = 5.
Therefore, the required number is 35.
⬆HOPE THIS HELPS YOU⬅
Let us consider that the digits are x and y.
Then, the number is = (10x + y)
When, digits are interchanged, the number becomes (10y+x).
Given that :
x + y = 8 .....(i)
and
10y + x = (10x + y) + 18
=> 9y = 9x + 18
=> y = x + 2
Now, putting y = x + 2 in (i), we get :
x + x + 2 = 8
=> 2x = 6
=> x = 3
Hence, y = 5.
Therefore, the required number is 35.
⬆HOPE THIS HELPS YOU⬅
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