Question

The sum of the digits of a 2- digit number is 8. The number obtained by interchange is exceeds by 18 . Find the give numbers

Answer 1

Here's the answer :

Let the number at the tenth digit be x.

One' s digit number = (8-x)

Number =
10 (x) + (8-x)
10x + 8 - x
10x - x + 8
9x + 8



Reversing Number =
10 (8-x ) +x
80 - 10x + x
80 - 9x



According to Question!

(9x + 8) + 18 = (80 - 9x)
9x + 8 + 18 = 80 -9x
9x + 9x = 80 - 8 - 18
18x = 54
x = 54 /18
x = 3




Tenth digit number = x = 3

One's digit number = 8-x = 8-3 = 5




Number =
10 × 3 + 1 × 5
30 + 5
35


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