The sum of the digits of a 2 digit number is 9. [4] If the digit in the tens place is considered as , the digit in the units place in terms of will be _________ (a) −9 (b) 9− (c) 9+ (d) 10+9
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PLease brainliest (through this yyou can get idea)
Step-by-step explanation:
Let the ten's digit no. be x and one's digit no. be y.
So the no. will be = 10x+y.
Given : x+y=9-----(I)
9(10x+y)=2(10y+x) ⇒88x−11y=0 -----(II)
On solving I and II simultaneously you will get x=1 and y=8.
Therefore your desired no. is 18.
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