Question

The sum of the digits of a 2-digit number is 9. If the number formed by reversing its digits is 27 less

than the original number, find the original number.​

Answer 1

Let the unit digit be y and tens digit be x

Number formed = 10x + y

Reverse number = 10y + x

x + y = 9 (Given)…………………………eq1

10y + x = 10x + y + 27…………………….eq2

9y - 9x = 27

y - x = 3……………………………………..eq3

Solving eq1 and eq3 ,we get

x = 3 and y = 6

Original Number = 36 Reversed Number = 63