Question

The sum of the digits of a 2-digit number is 9. If the number formed by reversing its digits is 27 less

than the original number, find the original number.

plzz guys help me.
this is a doubt for my tomorrow exam
plzz help me​

Answer 1

Answer:

63

Step-by-step explanation:

Let the number be AB

A+B=9

A=9-B

Now, here A is at tens digit and b at ones digit. So it becomes,

10A+B

= 10(9-B) + B

= 90 - 10B + B

=90-9B

Interchanging the digits, it becomes

10B+A

= 10B + (9-B)

= 9B+9

Now, it is given that new number is 27 less than original number,

So

9B+9 + 27= 90-9B

9B+36=90-9B

9B+9B=90-36

18B=54

B=54/18

B= 3

So, A= 9-3= 6

So the number is 63.