Question

The sum of the digits of a 2 digit number is 9 if the number formed by reversing its digits is 27 less than the original number​

Answer 1

Answer:

your answer.........

Answer 2

Step-by-step explanation:

Let the ones place number = y

tenth place number = x

The number = 10x + y (x+y given)

after reversing

The number = 10y + x

According to question

10x + y = 10y + x + 27

10x - x = 10y - y + 27

9x = 9y + 27

9x - 9y = 27

9(x - y) = 27

x - y= 27 ÷ 9

x - y= 3

x = 3 + y

x + y = 9

x = 9 - y

x = 9 - y = 3 + y

9 - y = 3 + y

9 - 3 = y + y

6 = 2y

3 = y

x + y = 9

x + 3 = 9

x = 9 - 3

x = 6

The number is XY = 63