the sum of the digits of a 2 digit number is 9. on reversing its digits, the new number obtained is 45 more than original number. find the number
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T O
x 9-x
Original number = 10*x + 1*9-x
= 9x+9
T O
9-x x
New number = 10*9-x + 1*x
= 90-9x
ATQ,
9x+9+45= 90-9x
9x+54 = 90-9x
9x+9x= 90-54
18x=36
x=36/18
x=2
9-x=9-2=7
Original number = 27
x 9-x
Original number = 10*x + 1*9-x
= 9x+9
T O
9-x x
New number = 10*9-x + 1*x
= 90-9x
ATQ,
9x+9+45= 90-9x
9x+54 = 90-9x
9x+9x= 90-54
18x=36
x=36/18
x=2
9-x=9-2=7
Original number = 27
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