The sum of the digits of a 2 digit number is 9.On reversing the digits, the new number.obtained is 45 more than the original number. Find the number.
Answers
Answered by
3
Answer:
Given that
a + b = 9 and
[(a•10) + b] + 45 = (b•10) + a
Part 1: simplify 2nd equation
10a + b + 45 = 10b + a
45 = 9b - 9a
45/9 = b - a
5 = b - a
Part 2: eliminate one variable to solve for other variable
5 = b - a summed with
9 = a + b equals
14 = 2b
b = 7
Part 3: solve for second variable
If a + b = 9 and
b = 7, therefore
a = 2
Part 4: convert a and b digits to 2-digit numbers
Converting a and b to place-digits in 2-digit number:
if a = 2 and b = 7, the two numbers are
27 and 72
27 + 45 = 72
Answered by
16
Step-by-step explanation:
The number obtained by reversing the digits is 10y + x. ATQ, reversed number is 45 more than original number.
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