Question

The sum of the digits of a 2-digit number is 9. The number is 6 times the units digit. Find the number.

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Answer 1

Answer:

The digit in the tens place is x

The digit in the ones place is y

The number is (10x + y)

Form equation 1 :

The sum of the digits is 9

x + y = 9

x = 9 - y

Form equation 2 :

The number is 6 times the units

10x + y = 6y

Put the two equations together:

x = 9 - y -------------------- [ 1 ]

10x + y = 6y -------------------- [ 2 ]

Find y:

Sub [ 1 ] into [ 2 ]:

10(9 - y) + y = 6y

90 - 10y + y = 6y

90 - 9y = 6y

15y = 90

y = 90 ÷ 15

y = 6

Find x:

When y = 6

x = 9 - 6

x = 3

Find the number

The number = 10x + y

The number = 10(3) + 6

The number = 36

Answer: The number is 36

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Answer 2

The sum of two digit number is 9.

t + u = 9

u = (9-t)

The number is 6 times the unit digit.

10t + u = 6u

10t + u - 6u = 0

10t - 5u = 0

10t - 5(9-t) = 0

10t - 45 + 5t = 0

10t + 5t = 45

15t = 45

t = 45/15

t = 3 is the tens digit

then

9-3 = 6 is units digit

:

Find the number? 36