Question

the sum of the digits of a 2-digit number is 9. The number is 6 times the units digit . Find the number

Answer 1

Hope it helps....!!!
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=> Set t = the tens digit

=> u = the units digit

=> t + u = 9

Solve for t by adding -u to each side.

=> t = 9 - u

The value of the number is 10t + u.

=> (10t + u) = 6u

Substitute (9 - u) for t in the above

=> 10(9 - u) + u = 6u
=> 90 - 10u + u = 6u
=> 90 - 9u = 6u

Add 9u to each side

=> 90 = 15u

Divide each side by 15

=> 6 = u

Since t+u = 9

=> t + 6 = 9

Add -6 to each side

=> t = 3

Since t+u = 9, 3+u = 9 and u = 6

=>So our number is 36.
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Answer 2

Let the digit be 6x and x
A/Q
6x+x=9
7x=9
X=9/7