Question

The sum of the digits of a 2-digit number is 9. When the digits are reversed, it is found that the resulting number is greater than the original number by 27. Find the number. s answer fast

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Answer 1

Answer:

Let the digits be x and y.

Then, x+y = 9

the original number is 10x+y.

On reversing, we get the new number as 10y+x

The new number is greater than the old number by 27, i.e.

(10y+x) - (10x+y) = 27

or 9y-9x = 27, or y-x = 3

and x+y = 9

Adding the two equations, we get 2y = 12 or y = 6.

Thus, x = 3.

Therefore, the original number is 36.

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Answer 2

Let the digit in ones place be x and the digit in tens place be 9-x.

Orginal number = 10(9-x)+x = 90-9x

New number = 10x+9-x = 9x+9

(9x+9)-(90x-9) = 27

9x+9-90x+9x = 27

18x-81 = 27

18x = 108

x = 6

Original number = 36

New number = 63

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