the sum of the digits of a 2 digits number is 10. The number obtained by interchanging the digits exceeds the orignal number is 36. find the orignal number
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ORIGINAL NO.=xy
THERE SUM OF NO.=x+y=10...........(1 )
ON INTERCHANGING THE NUMBER
(10y+x)=(10x+y)+36
9y-9x=36
y-x=4..................... (2)
ADDING 1 AND 2
2y=14
y=7
putting the value of y in equation (1)
we get x= 3
The original no. of xy is 37
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