Question

The sum of the digits of a 2 digits number is 8. When 18 is added to the number, the digits of the sum obtained are reverse of those of the number . Find the original number.

Answer 1

Answer:

let the tens digit be. x

let the ones digit be y

so the no. is 10x+y.

ATQ,

x+y=8 .

(10x+y)+18=10y+x

10x+y-10y-x=-18

9x-9y=-18

9(x-y)=-18

x-y=-2

so by elimination method

x+y=8

x-y=-2

2x=6

x=3

x+y=8

3+y=8

y=5

hence the no.is 35