Question

the sum of the digits of a 2 digits numberis 10. if we reverse the digits the new number will be 54 more than the original number what is the original
.

Answer 1

let digit be x and y
x+y=10.......(1)

orignal no. is 10x+y
after reversing
new no. is 10y+x

A/q
new no. =54 + orignal no.
10y+x = 54 + 10x+y
9y -9x = 54
y - x = 54/9=6........(2)

from 1 and 2

y - (10 - y)=6
y- 10+ y=6
2y = 6+ 10
y = 16/2
y = 8

x= 10-8
x = 2

orignal no. 10×2+8=28

Answer 2

Answer:

Step-by-step explanation:

let digit be x and y

x+y=10.......(1)

orignal no. is 10x+y

after reversing

new no. is 10y+x

A/q

new no. =54 + orignal no.

10y+x = 54 + 10x+y

9y -9x = 54

y - x = 54/9=6........(2)

from 1 and 2

y - (10 - y)=6

y- 10+ y=6

2y = 6+ 10

y = 16/2

y = 8

x= 10-8

x = 2

orignal no. 10×2+8=28

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