The sum of the digits of a 2 digits numbers is 7. The number formed by reversing the digits is 45 more than the original number. Find the original number.
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Answer: 16
Step-by-step explanation:
let the digit on ones place be x and that on tens place be y
x+y=7
y=7-x
Original number = 10y+x=10(7-x)+x=70-10x+x
=70-9x
Reversed number=10x+y = 10x + 7 - x = 9x+7
Original number +45 = reversed number
70-9x+45 = 9x+7
70+45-7=18x
108=18x
x=6
original number = 70-9x = 70 - 54 = 16
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