Question

The sum of the digits of a 2digit number less than 20 is 5 .find the number and the number formed by reversing its digits.
can someone pls explain with the steps
urgent I will mark brainiest to the best answer
pls explanation is needed
unhelpful answers are not encouraged!!!
pls help me !!!!!

Answer 1

Answer:

let the unit place digit be x and tens place digit be y

then the two-digit number will be  10y + x

and the number formed by interchanging the unit place and tens place digits will be 10x + y

according to the first condition given in the qs i.e, the sum of two numbers is 110 that  is

10y + x + 10x + y = 110

=> 11x + 11y = 110

divide the above equation by 11 we get

x + y = 10

x = 10 - y ....(i)

now according to the second equation,

if 10 is subtracted from the first number i.e, the new number is  10y + x - 10

given that the new number is 4 more than 5 time the sum of its digits in the first number i.e

the sum of its digits in the first number is  x + y,  now 5 times of its, 5(x + y), and now 4 more that is, 4 + 5(x + y)

therefore new number = 4 + 5(x + y)

10y + x - 10 = 4 +5(x + y)

10y - 5y + x = 4 +10 +5x

5y = 14 + 4x.....(ii)

substitute the value of x from eq(i) to eq (ii)

we  get , 5y = 14 + 4(10 - y)

5y = 14 + 40 - 4y

y = 6

and from eq(i)

x = 4

then the first number 10y + x = 10x6 + 4 = 64

first number is 64.

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Answer 2

Answer:

14

Step-by-step explanation:

The number formed by reversing 14 is 41. (1+4=5)

We can find it by trying to add the 2 digit numbers less than 20. (That is from 19 to 10)

If we take

19 then 1 + 9 = 10

18 then 1 + 8 = 9  

17 then 1 + 7 = 8  

16 then 1 + 6 =7

15 then 1 + 5 = 6

14 then 1 + 4 = 5

Hope it Helps!!