Question

the sum of the digits of a certain two digit number is 10 if the digit are reseversed a new number formed which is one less than the twice the original number find the numbers ​

Answer 1

Answer:

unit digit be X

ten's digit = 10-x

number formed = 10(10-x) + X = 100 - 9x...........(1)

if the digit gets reversed number formed = 9x+10.................(2)

now equate both the equations and you will get 7 as unit digit and 3 as ten's digit number formed = 37