The sum of the digits of a given two digit number is 5. If the digit are reversed the new number is reduced by 27. Find the given number
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Given:
The sum of the digits of a given two digit number is 5.If the digit are reversed the new number is reduced by 27.
To find:
The given number
Solution:
Let x be the digit of ten's place and y be the digit at unit place.
Given that x + y = 5......(1)
According to the question
10x + y = 5
after reversed the number will be 10y + x
Given, Original number - reversed number = 27
(10x + y) - (10y + x) = 27
10x - x + y - 10y = 27
9x - 9y = 27
Now, 9x = 27 or 9y = 27
x = 27/9 or y = 27/9
x = 3 or y = 3
Now, in the equation,
x - y = 3.........(2)
Also from (1), y = 5 - x....(3)
Substitute (3) in (2) to get x-(5-x) = 3
x - 5 + x = 3
2x = 3 + 5
2x = 8
x = 4 ( by dividing)
Substitute x = 4 in (3)
y = 5 - 4 (substituting x value)
y = 1
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