Question

the sum of the digits of a given two digit number is 5. if the digits are reversed,the new number is reduced by 27 .find the given number​

Answer 1

: Let the digits be x and y respectively.

Therefore, x + y = 5 ----------- (1)

Original Number : 10x + y

Reversed Number :  10y + x

10x + y - (10y + x) = 27

10x + y - 10y - x = 27

9x - 9y = 27

9 (x - y) = 27

x - y = 3 ------------ (2)

Adding equation (1) and (2)

2x = 8

x = 4

Substituting value for x in equation (1), we get

4 + y = 5

y = 1

The numbers are 41 and 14.

Answer 2

Answer:

41

Step-by-step explanation:

Let the units digit be x.

The tens digit =5−x

Original number =10(5−x)+x=50−9x

If digits are reversed, number is reduced by 27.

50−9x−27=10x+5−x

23−9x=9x+5

18x=18

∴x=1

Tens place =5−1=4

Therefore, the number is 41.

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