The sum of the digits of a number is 13, and the difference between the number and that formed
reversing the digits is 27: find the numbers.
A certain number of two digits is three time the sum of its digits, and if 45 be added
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The sum of the digits of a number is 13, and the difference between the number and that number and that number and that formed by reversing the digits is 27 find the numbers?
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Lets assume a 2 digit number xy.
We can express xy as [math]10*x+y[/math]
Now according to given scenario-
[math]x+y=13[/math]-(1)
Also,
[math]10*x+y-10*y-x=27[/math]
This implies
[math]9*x-9y=27[/math]
Hence
[math]x-y=3[/math]-(2)
Adding 1 and 2 we get -
[math]2*x=16[/math]
Hence x=8
Substituting x in (
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