Question

the sum of the digits of a ten digit number is 9 if the digits are reversed the number is 63 more than the original .Find the number​

Answer 1

Answer:

Let

x

be the ones digit

⇒

The tens digit is

9

−

x

10

(

9

−

x

)

+

x

+

63

=

10

x

+

(

9

−

x

)

⇒

90

−

10

x

+

x

+

63

=

10

x

+

9

−

x

⇒

153

−

9

x

=

9

x

+

9

⇒

153

−

9

=

18

x

⇒

144

=

18

x

⇒

x

=

8

⇒

9

−

x

=

9

−

8

=

1

Therefore, the number we are looking for is

10

(

1

)

+

8

=

18