Question

the sum of the digits of a three - digit number is 11. if the digits are reversed the new number is 46 more than five times the former number if the hundred digit plus twice the tens digit is equal to the units digit then find the original three digit number ​

Answer 1

Answer:

Let the tens digit be x.

Hence, the units digit will be 2x

Number =10×(x)+(2x)=12x

When 36 is added to the number, the new number formed =12x+36

As the digits are reversed, we can also write the new number as 10×(2x)+x=21x

Hence,

12x+36=10×(2x)+x

⇒12x+36=21x

⇒21x−12x=36

⇒9x=36

⇒x=4

Hence, the original number =12x=12×4=48

Step-by-step explanation:

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