The sum of the digits of a three - digit number is 12. If we subtract 495 from the number consisting of the same digits written in reverse order, we shall get the required number. Find that three - digit number if the sum of all pairwise products of the digits constituting that number is 41.
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Step-by-step explanation:
No(1)Its better if we do option verification.
The answer could be 863.
coz we have x+y+z=17
100x+10y+z-495=100z+10y+x ie x-z=5
using this we can have
2z+y=12, by trial and error we have 863
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