Question

The sum of the digits of a three - digit number is 12. If we subtract 495 from the number consisting of the same digits written in reverse order, we shall get the required number. Find that three - digit number if the sum of all pairwise products of the digits constituting that number is 41.​

Answer 1

Step-by-step explanation:

No(1)Its better if we do option verification.

The answer could be 863.

coz we have x+y+z=17

100x+10y+z-495=100z+10y+x ie x-z=5

using this we can have

2z+y=12, by trial and error we have 863