Question

The sum of the digits of a three-digit number is 16. The tens digit is one less than the hundreds digit and the ones digit is half the tens digit. If the digits are reversed, the number decreases by 396. Find the number.​

Answer 1

Answer:

The number is 862.

Step-by-step explanation:

Let the hundredth's digit of the number be x.

Then unit's digit =

$\frac{x}{4}$

and ten's digit =

$\frac{3x}{4}$

Given,

The sum of the digits is 16

$x + \frac{x}{4} + \frac{3x}{4} = 16$

$\frac{4x + x + 3x}{4} = 16$

$2x = 16$

$x = 8$

ten's digit =

$\frac{3x}{4} = \frac{3 \times 8}{4} = 6$

unit's digit =

$\frac{x}{4} = \frac{8}{4} = 2$

∴ Required number = 100×8+10×6+2

=800+60+2=862

The required number is 862....

Pls mark as brainliest.

Answer 2

763 is the right answer of this question