Question

The sum of the digits of a two-degit number is 9. If the digits are reversed, the number is increased by 45. Find the original number.​

Answer 1

Answer:

27

Step-by-step explanation:

Let the tens digit of the number be x and units digit of the number be y

The number will be 10x + y

x + y = 9 (1)

10y + x = 10x + y + 45

=> 9x - 9y = -45

=> x - y = -5 (2)

Adding equations (1) and (2),

x + y = 9

x - y = -5

2x    = 4

=> x = 4/2

=> x = 2

In equation (1),

x + y = 9

=> 2 + y = 9

=> y = 7

Therefore, the original number is 27.

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