Question

the sum of the digits of a two digit no. is 11 the given no. is less than th no. obtained by interchanging the digits by 9 . find the no.​

Answer 1

Two digit number: xy= 10x+y.

Sum of digits: x+y=11

xy is less then yx by 9: xy+9=yx

xy+9=yx

10x+y=10y+x-9

9x-9y=-9

x-y=-1,

So this is the system of equations to be solved:

x + y=11

x - y =-1

x=5, y=6

The number is 56.

$hope \: it \: helps \: you \: and \: please \: mark \: it \: as \: brainliet$