the sum of the digits of a two digit no. is 15 if the no. obtained by reversing the order of the digits of the given no. exceeds the given no. by 9 find the given no.
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Step-by-step explanation:
Let the tens,unit digit of number be=x,y respectively
Here xy=10x+y
⇒x+y=15
Second condition :
⇒10y+x=9+10x+y
⇒9x−9y=−9
⇒x−y=−1
Add resultant equations ;
⇒2x=14
⇒x=7
⇒y=8
∴two digit number =78
Hope it helps
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