The sum of the digits of a two-digit no. is 7. The no. obtained by interchanging the digits exceeds the original no. by 27. Find the number?
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x+y=7
(y*10+x)-(x*10+y)= 27
on solving this we get
-9x + 9y=27
-x+ y =3
so y=5 x= 2
numbers are 25 and 52
(y*10+x)-(x*10+y)= 27
on solving this we get
-9x + 9y=27
-x+ y =3
so y=5 x= 2
numbers are 25 and 52
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