Math, asked by Nithish123456, 8 months ago

The sum of the digits of a two digit no. is 9. Number formed by interchanging the digits is 45 more than the original no. Find the original no. and check the solution.

Answers

Answered by anithanix
1

Answer:

27

Step-by-step explanation:

72 = 27 +45

=72

please give brainliest

Answered by Anonymous
0

Answer:

Let the tens digit of the number be x.

And the unit digit be y.

Two digit number = 10x + y

Number formed by interchanging the digits = 10y + x

According to condition,

x + y = 9 - - - - ( 1 )

According to second condition,

10y + x = 10x + y + 45

⟶ 10y + x - 10x - y = 45

⟶ 9y - 9x = 45

⟶ y - x = 5 - - - ( Diving by 9 ) - ( 2 )

Now,

x + y = 9 - - - - ( 1 )

- x + y = 5 - - - ( 2 )

_____________

⟶ 2y = 14 ( Adding both equations )

⟶ y = 14 / 2

⟶ y = 7

Put y = 7 in equation ( 1 ),

⟶ x + y = 9

⟶ x + 7 = 9

⟶ x = 9 - 7

⟶ x = 2

The original number = 10x + y

⟶ 10 × 2 + 7

⟶ 20 + 7

⟶ 27

The original number is 27.

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