The sum of the digits of a
two-digit number 12 ,if the
digits are reversed, the new number is 4/7 the times the original number Determine the original number
Answers
Answered by
194
Answer:
Step-by-step explanation:
Given:-
- Sum of digits of two-digit number = 12
- Digits reversed,new number = 4/7 times original number.
To find:-
- The original number = ?
Let the one's digit be a and ten's digit be b.
A/Q,
1st case:-
2nd case:-
* Number :-
=
BrainlyConqueror0901:
keep it up bro : )
Answered by
242
Step-by-step explanation:
Here you go ☆☆
▪let digit at ones place = x
and at tens place= y
▪so, no. is 10y + x
▪given, y+x= 12------《1》
▪if no. is reversed , then
▪10x+ y = 4/7(10y +x)
▪10x-4/7x + y -40/7y
66/7x-33/7y = 0
▪multiply term with 7 , we get ,
▪66x -33y = 0
taking 33 as common,
▪2x -y =0------《2》
▪by elimination method,
multiply 1 by 2 and subtract 2 from 1 ,we get,
▪2x +2y =24
▪2x - y = 0
- + -
▪3y = 24
▪y = 8
▪so x= 4
▪so original no.= 84
hope it helps you....
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