Question

The sum of the digits of a two digit number 9.Also nine times this number is twice obtained by reversing the order of the digits. Find the number.

Answer 1

Hope this helps!!!!!
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Let tens digit no.be X and unit digit no.be Y 
A/q

x+y=9
and 9 (10×x+y)=2 (10×y+x)
90x+9y=20y+2x
88x-11y=0

from 1st 
11x+11y=99
88x-11y=0
......
99x=99
x=1

and y=8 hence the no.is 18
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Answer 2

Here is your solution

Given :-

The sum of the digits of a two digit number is 9

Let
The digits be x and y, and the number be 10x + y.

I. e

x + y = 9 ------ (1)

Now
A/q

9×(10x + y) = 2×(10y + x)

90x + 9y = 20y + 2x

88x = 11y

y = 8x ---- (2)

putting the value of y in equation (1.) we get,

x + 8x = 9
9x = 9.
x = 1

y = 8×1 = 8.

Hence

The number is 10x +y = 10×1 + 8 = 18.

Hope it helps you