Question

the sum of the digits of a two digit number 9. also nine times this number is twice the number obtained by reversing the order of the digits. find the number. by elimination method

Answer 1

HEY DEAR ... ✌️

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Here's , ur answer :-


Let tens digit no.be X and unit digit no.be Y 


A/q


x+y=9


and 9 (10×x+y)=2 (10×y+x)


90x+9y=20y+2x


88x-11y=0


from 1st 


11x+11y=99


88x-11y=0


99x=99


x=1


and y=8 hence the no.is 18


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HOPE , IT HELPS ... ✌️

Answer 2

Here is your solution

Given :-

The sum of the digits of a two digit number is 9

Let
The digits be x and y, and the number be 10x + y.

I. e

x + y = 9 ------ (1)

Now
A/q

9×(10x + y) = 2×(10y + x)

90x + 9y = 20y + 2x

88x = 11y

y = 8x ---- (2)

putting the value of y in equation (1.) we get,

x + 8x = 9
9x = 9.
x = 1

y = 8×1 = 8.

Hence

The number is 10x +y = 10×1 + 8 = 18.

Hope it helps you