The sum of the digits of a two-digit number is 1/7of the number. If the digits are reversed.the new number becomes 18 less than the original number. Find the number.
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Answer:
The digits are 4 and 2.
Step-by-step explanation:
Let the digits be x and y
x+y=1/7×(10x+y)
7(x+y)=10x+y
7x+7y=10x+y
7y-y=10x-7x
6y=3x
2y=x---------☆
Also,
10y+x=10x+y-18
10y-y=10x-x-18
9y=9y-18
18=9x-9y
18=9(x-y)
2=x-y
x-y=2
2y-y=2(From ☆)
y=2
x-y=2
x-2=2
x=2+2
x=4
HOPE THIS BRING A SMILE IN YOUR FACE
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