Question

the sum of the digits of a two digit number is 10 and the digits at its units place is 2/3 of the digit at the tens place. please answer quickly .​

Answer 1

Answer:

Step-by-step explanation:

Let the digits be x and y.

x + y = 10 ------- (1)

y = 2/3 * x -------(2)

Substitute (2) in (1),

x + 2x/3 = 10

5x/3 = 10

x = 30/5 = 6

y = 4.

Thus the number is 64.