The sum of the digits of a two digit number is 10. And the number obtained by reversing its digit is 18 less then the original number.find the original number?
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use the 1th no. as 10x+y and the 2nd as 10y+x.
praveshchaurasia5:
plz tell me full solution
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64 and 46
Answered by
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a+b=10 ---------(1)
the original no. =10a+b
reversed no. =10b+a
10a+b - 18=10b+a
9a-9b=18
a-b=2 -----(2)
Adding equation (1) and (2).
a-b+a+b=10+2
2a=12
a=6
value of b
a+b=10
b=10-6=4
original no. =10×6+4=64
HOPE THIS WILL HELP U
the original no. =10a+b
reversed no. =10b+a
10a+b - 18=10b+a
9a-9b=18
a-b=2 -----(2)
Adding equation (1) and (2).
a-b+a+b=10+2
2a=12
a=6
value of b
a+b=10
b=10-6=4
original no. =10×6+4=64
HOPE THIS WILL HELP U
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