Question

the sum of the digits of a two digit number is 10. if 18 be subtracted from it the digits in the resulting number will be equal the number is​

Answer 1

Step-by-step explanation:

let the two digits be a and b

a+b=10

i think your question is wrong but iwill do it by assumepotion

a-b=18

2a=28(by adding two equ)

a=14

put the value of a

14-b=18

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Answer 2

x = 10's digit of a two digit number(Let)

y = units digit(Let)

n=Resulting equal digits(Let)

Condition 1-the sum of a two digit number is 10

x + y = 10

further simplifying

y = (10-x)

Condition 2-if 18 be subtracted from it the digits in the resulting number will be equal

10x + y - 18 = 10n + n

10x + y = 11n+ 18

Substitutituting values found above

10x + (10-x) = 11n + 18

10x - x = 11n + 18 - 10

9x = 11n+ 8

If we solve it we will found the values as - x = 7, y = 3, z = 5 and finally we can say the no. is 73.