the sum of the digits of a two digit number is 10 if 18 is added to the number it's digits are reversed. Find the number
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The question comprises of two data.
Data 1 :
The sum of digits of a two digit number is 10.
Data 2 :
If 18 is added to the number, it's digits are reversed.
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Let us consider that,
Two digit number = 10x + y
x, y are digits.
From data 1 ; x + y = 10
From data 2 ;
⇒ 10x + y + 18 = 10y + x
⇒ 9x - 9y = - 18
⇒ x - y = - 2
We have two equations now,
x + y = 10
x - y = - 2
⇒2x = 8
⇒ x = 4
Substituting in any equation, We get
⇒x + y = 10
⇒4 + y = 10
⇒y = 10 - 4
⇒y = 6
Therefore, The two digit number is 10(4)+6 = 40 + 6 = 46
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