The sum of the digits of a two-digit number is 10. If the digits are reversed, the new number is 18 less
than the original number. Find the numbers.
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The number formed by reversing the digits is 18 less than the original number. Hence, Original number = 64.
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Answer:
Let one digit at the unit place be y, then the other digit at the tenth place is (10 - y)
The value of the number would be 10 (10 - y) + y = 100 - 9y
On interchanging the digits, value would be 10y + (10 - y) = 9y + 10
According to question
100 - 9y = 9y + 10 + 18
18y = 100 - 28
18y = 72
y = 4
The original number is thus 64
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