Question

the sum of the digits of a two digit number is 10.if we reverse the digits,the new number will be 54 more than the original number.what is the original number?
Please answer this question​

Answer 1

Let unit digit is x

and ten's digit is y

Then, Original no.= x+10y

Reversing the digits=>

New no. = 10x + y

10x + y = x + 10y + 54

10x - x +y - 10y = 54

9x - 9y = 54

9(x-y) = 54

x - y = 6 - eq1

x + y = 10- eq2

Add eq 1 and eq2

2x = 16

x = 8

So, y = 2

Therefore :

Original Number = x + 10y = 28

Answer 2

Step-by-step explanation:

problem is solved in picture , chek there