Question

The sum of the digits of a two- digit number is 10. The number is decreased by 36 if the digits are reversed. Find the original number

Answer 1

Answer:

x+y=10

(10x-y)-36=10y+x

10x-x-36=10y-y

9x-36=9y

9x-9y=36

x-y=4

x+y=10

x-y=4

solving by elimination

x=7

y=3

number=73