The sum of the digits of a two digit number is 10. The number obtained by
interchanging the digits exceeds the original number by 36. Find the original
number.
Answers
Answered by
0
Answer:
I don't know..................???????!!!!!@#$^
Answered by
0
Answer:
Step-by-step explanation:
ones digit no.= x
tens digit no.= 10-x
so,
original no.= 10(10-x)+x
=100-9x
new no. = 10(x)10-x
= 9x+10
atq,
new no. - original no.=36
= 9x+10-100-9x = 36
= 90 + 18x = 36
=18x =90-36=54
= x =54/18 =3
so, x= 3
verification = ones digit no.= x =3
= tens digit no.= 10-x =7
new no. - original no.=36
73-37=36
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