Question

The sum of the digits of a two digit number is 10. The number formed by reversing the digits is 18 less than the original number. Find the original number?​​

Answer 1

Answer:

64

Step-by-step explanation:

x y are the digits

x+y = 10 equation 1

the original number is 10x+y

given reversing the digits is 18 less than the original number

10y+x+18 = 10x+y

10y-y+18 = 10x-x

9y-9x = -18

-9(x-y)=-18

9(x-y)=18

x-y = 2 equation 2

add equation 1 and 2

x+y+x-y = 10+2

2x = 12

x=6

x+y = 10

6+y = 10

y = 4

original number = 64