Question

The sum of the digits of a two digit number is 10. The number formed by reversing the digits is 18 less than the original number. Find the original number?​

Answer 1

Answer:

64

Step-by-step explanation:

First digit: x

Second digit: 10-x

Original Number: 10*x+(10-x)

=9x+10

The number formed by reversing the digits: 10*(10-x)+x

= 100-9x

ATQ

(9x+10)-(100-9x)=18

18x-90=18

18x=18+90

x=108/18

x=6

Final Number: x=6

10-x= 10-6= 4