the sum of the digits of a two-digit number is 10. the number obtained by interchanging the digits exceeds the original number by 36. find the original number.
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3
Answer:
37
Step-by-step explanation:
Let the units digit be x.
Tens digit = 10-x
Original number = 10(10-x)+x = 100-9x
After interchanging digits,
Units digit = 10-x
Tens digit = x
New number = 10x+10-x = 9x+10
According to Question,
100-9x+36 = 9x+10
=> 136-10 = 9x+9x
=> 126 = 18x
=> x = 7
Hence, original number = 37
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