Question

the sum of the digits of a two-digit number is 10. the number obtained by interchanging the digits exceeds the original number by 36. find the original number.

Answer 1

Answer:

37

Step-by-step explanation:

Let the units digit be x.

Tens digit = 10-x

Original number = 10(10-x)+x = 100-9x

After interchanging digits,

Units digit = 10-x

Tens digit = x

New number = 10x+10-x = 9x+10

According to Question,

100-9x+36 = 9x+10

=> 136-10 = 9x+9x

=> 126 = 18x

=> x = 7

Hence, original number = 37