Math, asked by aryandhakne13, 7 months ago

The sum of the digits of a two-digit number is 10. The number obtained
by reversing the order of the digits of the given number exceeds the given
number by 36. Find the given numb

Answers

Answered by nayan78989

0

Answer:

10x+(10-x)-10(10-x)+x=36

10x+10-x-100+10x=36

21x=126

x=6

The number is 46.

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