The sum of the digits of a two-digit number is 10. The number got by interchanging the digits is 36 less than the original number. Find the number.
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Answered by
0
Answer:
The answer is 73.
Step-by-step explanation:
As the digits have sum 10 and if interchanged then 36 less than original number
Answered by
0
Answer:
Let the tens digit of the required number be x and the units digit be y. Then,
x+y=12
Required Number = (10x+y).
Number obtained on reversing the digits = (10y+x).
Therefore,
(10y+x)−(10x+y)=18
9y−9x=18
y−x=2
On adding (1) and2), we get,
2y=14⟹y=7
Therefore,
x=5
Hence, the required number is 57.
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