the sum of the digits of a two digit number is 10 the number is discrete by 36 the digits are reversed find the original number
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Hello!!!
Here's your answer :
Let the tenth digit of number be x
One's digit = 10-x
Number =
10 (x) + (10 -x)
10x - x +10
9x + 10
According to question.
(9x + 10) - 36 = 10 (10 - x ) +x
9x + 10 - 36 = 100 - 10x + x
9x + 10 - 36 = 100 - 9 x
9x + 9x = 100 + 36 - 10
18x = 136 - 10
18x = 126
x = 126 /18
x = 7
Tenth digit = x = 7
One's digit = 10 - 7 = 3
Number = 10 × 7 + 1 × 3
70 + 3
73
Here's your answer :
Let the tenth digit of number be x
One's digit = 10-x
Number =
10 (x) + (10 -x)
10x - x +10
9x + 10
According to question.
(9x + 10) - 36 = 10 (10 - x ) +x
9x + 10 - 36 = 100 - 10x + x
9x + 10 - 36 = 100 - 9 x
9x + 9x = 100 + 36 - 10
18x = 136 - 10
18x = 126
x = 126 /18
x = 7
Tenth digit = x = 7
One's digit = 10 - 7 = 3
Number = 10 × 7 + 1 × 3
70 + 3
73
MantejSingh14:
I was struggling with this question thank you thank you
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