Question

the sum of the digits of a two digit number is 10 .the tens digit is 4 the times the one place digit find the number​

Answer 1

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Given :-

• The sum of the digits of a two digit number is 10.
• The tens digit is 4 the times the one place digit.

To Find :-

• The two digit number.

Solution :-

Let the two digit number be 10x + y.

Where x represent the 10s place and y represent the ones place.

According to the given question :

• x + y = 10 (The sum of the digits of a two digit number is 10)
• x = 4y (The tens digit is 4 the times the one place digit)

Therefore :

x + y = 10

Substituting x = 4y in the above equation:

4y + y = 10

5y = 10

y = 10/5

• y = 2

Substituting the value of y :

x + y = 10

x + 2 = 10

x = 10 - 2

• x = 8

Therefore, the 2 digit number is 10x + y :

10x + y

10(8) + 2

= 82

Final Answer :

• 82

@SweetestBitter

Answer 2

Answer:

Let the two digit number be 10x + y.

Where x represent the 10s place and y represent the ones place.

According to the given question :

x + y = 10 (The sum of the digits of a two digit number is 10)

x = 4y (The tens digit is 4 the times the one place digit)

Therefore :

x + y = 10

Substituting x = 4y in the above equation:

4y + y = 10

5y = 10

y = 10/5

y = 2

Substituting the value of y :

x + y = 10

x + 2 = 10

x = 10 - 2

x = 8

Therefore, the 2 digit number is 10x + y :

10x + y

10(8) + 2

= 82

Final Answer :

82